CUET UG 2023 Mathematics - 2nd June 2023 (Shift 3) Question Paper with Solution

# Q1 of 50

Corner points of a feasible bounded region are (0, 10), (4, 2), (3, 7) and (10, 6). Maximum value 50 of objective function z = ax + by occurs at two points (0, 10) and (10, 6). The value of a and b are:

Options
A.

a = 5, b = 2


B.

a = 4, b = 5

C.

a = 2, b = 5


D.

a = 5, b= 4


Show Answer
Correct Answer
C

a = 2, b = 5


Solution

The correct option is a = 2, b = 5.

We are given that the objective function is:
z=ax+by
The maximum value of the objective function z is given as 50, and it occurs at two corner points: (0, 10) and (10, 6).

First, let's substitute the point (0, 10) into the objective function equation:
z=a(0)+b(10)=50
10b=50
b=5010=5

Now, let's substitute the second point (10, 6) into the objective function equation with the maximum value of 50:
z=a(10)+b(6)=50
10a+6b=50

Substitute the value of b=5 we found earlier into this equation:
10a+6(5)=50
10a+30=50
10a=50-30
10a=20
a=2010=2

Thus, the values are a=2 and b=5.

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