Corner points of a feasible bounded region are (0, 10), (4, 2), (3, 7) and (10, 6). Maximum value 50 of objective function z = ax + by occurs at two points (0, 10) and (10, 6). The value of a and b are:
a = 5, b = 2
a = 4, b = 5
a = 2, b = 5
a = 5, b= 4
a = 2, b = 5
The correct option is a = 2, b = 5.
We are given that the objective function is:
The maximum value of the objective function is given as 50, and it occurs at two corner points: (0, 10) and (10, 6).
First, let's substitute the point (0, 10) into the objective function equation:
Now, let's substitute the second point (10, 6) into the objective function equation with the maximum value of 50:
Substitute the value of we found earlier into this equation:
Thus, the values are and .
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