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02:45:12
PHYSICS • SEC A

Q12. The potential energy of a particle in a force field is U = A/r² - B/r. Find the stable equilibrium distance.

2A/B
A/2B
B/2A
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Physics • Section A • Q7 of 30

A body of mass 5 kg is moving with velocity 10 m/s. What is the kinetic energy?

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Q12 U = A/r² - B/r. Find stable equilibrium distance...
JEE Advanced
AI Tutor Solution Solved in 0.3s
Step 1: Stable Equilibrium Condition

A particle is in equilibrium where conservative force F = -dU/dr = 0.

Step 2: Differentiating Potential Energy

d/dr [A·r⁻² - B·r⁻¹] = -2A·r⁻³ + B·r⁻² = 0 ⇒ r = 2A/B

30-Second Shortcut Trick:
For U = A/rⁿ - B/rᵐ, stable distance is directly r = (n·A / m·B)1/(n-m). Here: r = 2A/B!
Simpler terms 30s Shortcut Why option B? Common traps
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