2(C₅₁H₉₈O₆) + 145O₂ → 102CO₂ +98H₂O+energy The Respiratory Quotient (RQ) of a biomolecule used for respiration, as per the above equation, would be :

To find the Respiratory Quotient (RQ) we use the definition:

$RQ\; =\; \backslash frac\{\backslash text\{moles\; of\; \}CO\_\{2\}\backslash text\{\; produced\}\}\{\backslash text\{moles\; of\; \}O\_\{2\}\backslash text\{\; consumed\}\}$

From the given balanced reaction

2 C₅₁H₉₈O₆ + 145 O₂ → 102 CO₂ + 98 H₂O + energy

the stoichiometric coefficients tell us directly how many moles of each gas are involved:

• O₂ consumed = 145 mol
• CO₂ produced = 102 mol

Plug these numbers into the RQ formula:

$RQ\; =\; \backslash frac\{102\}\{145\}$

Perform the division:

$RQ\; \backslash approx\; 0.7034$

The resulting value lies between 0.5 and 0.95.

Therefore the correct choice is “Between 0.5 and 0.95”.