A device operates at 2 amperes current and 220 volts potential difference for 5 hours. How much electrical energy does it consume, expressed in kilowatt hours (kWh)?

The correct option is 2.2 kWh.

To find the electrical energy consumed by the device, we can follow these steps:

Step 1: Identify the given values
Current ($I$) = 2 amperes (A)
Potential difference ($V$) = 220 volts (V)
Time ($t$) = 5 hours (h)

Step 2: Calculate the electrical power in watts (W)
Power ($P$) is the product of voltage and current:

$P=V\times I$

Substitute the given values into the formula:

$P=220\text{V}\times 2\text{A}=440\text{W}$

Step 3: Convert power from watts (W) to kilowatts (kW)
Since 1 kilowatt (kW) = 1000 watts (W), we divide the power by 1000:

$P=\frac{440}{1000}\text{kW}=0.44\text{kW}$

Step 4: Calculate the total electrical energy consumed in kilowatt-hours (kWh)
Energy ($E$) is the product of power and time:

$E=P\times t$

Substitute the values of power in kW and time in hours:

$E=0.44\text{kW}\times 5\text{h}=2.2\text{kWh}$

Therefore, the device consumes 2.2 kWh of electrical energy.