Question Details

A hydraulic crane supports a mass of 500 kg with its piston cylinder actuator 60 cm, inclined at 60° with horizontal, as shown in figure. The diameter of the piston is 30 cm, acceleration due to gravity is 10 m/s². Neglecting mass of the piston, the reading of the pressure in kPa (gauge).

Options

A

70.71

B

35.35

C

6.13

D

61.26

Show Answer

Correct Answer :

Option D

61.26

Solution :

The correct option is 61.26.

Based on the provided diagram, we can identify the following parameters and details:
- A reservoir containing Oil with a Pressure gauge mounted on top.
- A piston-cylinder actuator inclined at an angle of 60° relative to the horizontal.
- A load of 500 kg supported by the piston shaft.

To find the gauge pressure reading, we carry out the calculations in the following steps:

Step 1: Calculate the weight of the supported mass
The downward force exerted by the mass due to gravity is the weight (W):

W=m·g

Given parameters:
- Mass, m=500 kg
- Acceleration due to gravity, g=10 m/s2

Substituting these values:

W=500 kg·10 m/s2=5000 N

Step 2: Determine the force component acting along the axis of the actuator
Since the cylinder is inclined at 60° with the horizontal, the axial force (F) acting along the piston axis to support the vertical load is:

F=W·sin(60°)

Substituting the weight value:

F=5000 N·sin(60°)=5000·0.8660254330.13 N

Step 3: Calculate the cross-sectional area of the piston
The diameter of the piston is given as 30 cm, which is 0.3 m. The cross-sectional area (A) is calculated as:

A=π4·d2

Substituting d=0.3 m:

A=π4·(0.3)2=π4·0.090.070686 m2

Step 4: Calculate the gauge pressure
The pressure (P) exerted on the oil by the piston is the axial force divided by the area of the piston:

P=FA

Substituting the values of F and A:

P=4330.130.07068661258.7 Pa

Converting the pressure to kPa:

P=61258.7100061.26 kPa

Therefore, the reading of the pressure gauge is 61.26 kPa (gauge).

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