Directions: Use the given day and date information to answer the question.

Meera was born on 22 March 2016, a Tuesday. On which day of the week will her 12th birthday, 22 March 2028, occur?

The correct answer is Wednesday.

To find the day of the week on 22 March 2028, we need to calculate the number of odd days between 22 March 2016 and 22 March 2028.

Step 1: Find the total number of years
The time duration from 22 March 2016 to 22 March 2028 is exactly 12 years.

$2028-2016=12\text{years}$

Step 2: Identify the number of leap years and ordinary years
A year adds an extra leap day (29 February) to our count only if 29 February falls within the given date range (22 March 2016 to 22 March 2028):
- 2016: 29 February 2016 occurred before 22 March 2016, so it is not included.
- 2020: Includes 29 February 2020 (1st leap year).
- 2024: Includes 29 February 2024 (2nd leap year).
- 2028: 22 March 2028 is after 29 February 2028, so 29 February 2028 is included (3rd leap year).

Thus, out of the 12 years, there are 3 leap years and 9 ordinary years:

$\text{Ordinary years}=12-3=9$

Step 3: Calculate the total number of odd days
- An ordinary year has 365 days, which equals 52 weeks and 1 odd day.
- A leap year has 366 days, which equals 52 weeks and 2 odd days.

Odd days from 9 ordinary years:

$9\times 1=9\text{odd days}$

Odd days from 3 leap years:

$3\times 2=6\text{odd days}$

Total odd days:

$9+6=15\text{odd days}$

Step 4: Simplify total odd days
Dividing 15 by 7 gives 2 full weeks with a remainder of 1 day:

$15÷7=2\text{weeks and}1\text{odd day}$

Step 5: Determine the final day of the week
Starting from Tuesday (22 March 2016), we add 1 day:

$\text{Tuesday}+1\text{day}=\text{Wednesday}$

Therefore, Meera's 12th birthday on 22 March 2028 will occur on a Wednesday.