Question Details

A square loop with each side 1 cm, carrying a current of 10 A, is placed in a magnetic f ield of 0.2 T. The direction of the magnetic field is parallel to the plane of the loop. The torque experienced by the loop is ______.

Options

A

zero

B

2 ×10−4 Nm

C

2 ×10−2 Nm

D

2 Nm

Show Answer

Correct Answer :

Option A

zero

Solution :

The correct option is zero.

Step-by-step Explanation:
The torque experienced by a current-carrying loop in a uniform magnetic field is given by the vector cross product of the magnetic dipole moment of the loop and the magnetic field vector:
τ = M × B

where:
M is the magnetic dipole moment of the loop (having magnitude M = I A, where I is the current and A is the area of the loop).
B is the magnetic field intensity.

In scalar terms, the magnitude of the torque is expressed as:
τ = M B sin ( θ )

Here, θ represents the angle between the direction of the magnetic dipole moment vector M (which is perpendicular to the plane of the loop) and the magnetic field vector B.
When the magnetic field is aligned such that the cross product between the magnetic dipole moment of the loop and the magnetic field vector equals zero, the loop experiences no rotational effect. Thus, the torque experienced by the loop is zero.

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