Question Details

A thick current carrying cable of radius ‘R’ carries current ‘I’ uniformly distributed across its cross-section. The variation of magnetic field B(r) due to the cable with the distance ‘r’ from the axis of the cable is represented by :

Options

A

B

C

D

Show Answer

Correct Answer :

Option A

Solution :

The correct graph representing the variation of the magnetic field B(r) with distance r from the axis of the cable is:

Step-by-Step Explanation:

Let a thick cylindrical cable of radius R carry a total current I uniformly distributed across its cross-sectional area A=πR2.

To find the magnetic field B at a distance r from the central axis of the cable, we analyze two regions using Ampere's Circuital Law:

Case 1: Inside the cable (rR)

Consider a circular Amperian loop of radius r concentric with the axis of the cable.

The current enclosed by this loop, Ienclosed, is proportional to the fraction of the cross-sectional area inside the loop:

Ienclosed=I×πr2πR2=Ir2R2

Applying Ampere's Circuital Law:

B·dl=μ0Ienclosed

B(2πr)=μ0Ir2R2

Simplifying for B:

Bin=μ0Ir2πR2

Therefore, inside the cable, Br. The magnetic field increases linearly from B=0 at the central axis (r=0) to a maximum value at the surface (r=R).

Case 2: Outside the cable (rR)

For an Amperian loop outside the cable (rR), the loop encloses the entire current I:

Ienclosed=I

Applying Ampere's Circuital Law:

B(2πr)=μ0I

Bout=μ0I2πr

Therefore, outside the cable, B1r. The magnetic field decreases non-linearly (hyperbolically) as r increases.

Conclusion:

The magnetic field graph starts at zero at the axis, increases linearly with r up to the surface r=R, reaches a peak, and then decreases as 1r for r>R. This characteristic shape is correctly depicted in the chosen graph.

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