Question Details

An amount of Rs. 12200 is partly invested in scheme A at 10% p.a. on compound interest for two years and in scheme B at the same rate on simple interest for four years. If the interest received from both the schemes is equal, then find the amount invested in scheme A?

Options

A

Rs.4350

B

Rs.4340

C

Rs.4200

D

Rs.8000

E

Rs.8500

Show Answer

Correct Answer :

Option D

Rs.8000

Solution :

The correct answer is Rs. 8000.

Let's break down the problem step-by-step to understand how to solve it.

Step 1: Understand the Given Information

Total amount available for investment = Rs. 12,200
Let the amount invested in Scheme A be PA.
Then, the amount invested in Scheme B is PB=12200-PA.
Rate of interest for both schemes (R) = 10% per annum (p.a.)

Step 2: Calculate Interest from Scheme A (Compound Interest)

Scheme A offers compound interest for a period of n=2 years.
The formula for the total amount A under compound interest is:

A=PA1+R100n

Substituting the given values into the formula:

A=PA1+101002=PA1.12=1.21PA

The Compound Interest (CI) earned from Scheme A is:

CI=A-PA=1.21PA-PA=0.21PA

Step 3: Calculate Interest from Scheme B (Simple Interest)

Scheme B offers simple interest for a period of T=4 years.
The Simple Interest (SI) formula is:

SI=PB×R×T100

Substituting the given values:

SI=PB×10×4100=40PB100=0.40PB

Step 4: Equate the Interests and Find the Ratio

According to the problem statement, the interest earned from both schemes is equal:

CI=SI

0.21PA=0.40PB

Multiplying both sides by 100 to eliminate decimals gives:

21PA=40PB

Therefore, the ratio of investments is:

PAPB=4021

Step 5: Calculate the Amount Invested in Scheme A

The total ratio parts equal:

40+21=61

Now, find the portion of the total amount (Rs. 12,200) allocated to Scheme A:

PA=4061×12200

Since 12200÷61=200:

PA=40×200=8000

Thus, the amount invested in scheme A is Rs. 8000.

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