An old woman decided to divide her gold among her daughter and daughters-in-law. She first kept exactly half of the gold for her daughter. Then she divided the rest of her gold among her daughters-in-law. The eldest one got 26 grams more than the youngest daughter-in-law. The middle one got twice as the youngest one. If the eldest daughter-in-law got 66 grams of gold, how much was received by the daughter?
Correct Answer :
186 grams
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