Question Details

Ankita walks from A to C through B, and runs back through the same route at a speed that is 40% more than her walking speed. She takes exactly 3 hours 30 minutes to walk from B to C as well as to run from B to A. The total time, in minutes, she would take to walk from A to B and run from B to C, is

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Correct Answer :

444

Solution :

The correct answer is 444.

Let us break down the solution step-by-step to understand the logical reasoning and calculations behind it.

Step 1: Understand the relationship between speeds and times
Let Ankita's walking speed be denoted as Vw and her running speed be denoted as Vr.
According to the problem, her running speed is 40% more than her walking speed. Therefore, we can express the running speed as:
Vr=Vw+0.40Vw=1.4Vw
Thus, the ratio of her walking speed to her running speed is:
VwVr=11.4=57

For a constant distance, speed and time are inversely proportional. Thus, the ratio of the time taken to walk a distance (Tw) to the time taken to run the same distance (Tr) is:
TwTr=75

Step 2: Calculate the times for individual segments
We are given that she takes exactly 3 hours 30 minutes to walk from B to C, and also to run from B to A.
First, convert this duration into minutes:
3 hours 30 minutes=(3×60)+30=210 minutes

For segment AB:
The time taken to run from B to A (which is the distance AB) is 210 minutes:
Tr(AB)=210 minutes
Using the time ratio TwTr=75, we can find the time she would take to walk from A to B:
Tw(AB)=Tr(AB)×75=210×75=42×7=294 minutes

For segment BC:
The time taken to walk from B to C (which is the distance BC) is 210 minutes:
Tw(BC)=210 minutes
Using the inverse ratio, we can find the time she would take to run from B to C:
Tr(BC)=Tw(BC)×57=210×57=30×5=150 minutes

Step 3: Calculate the total requested time
The total time she would take to walk from A to B and run from B to C is:
Ttotal=Tw(AB)+Tr(BC)
Substituting the calculated values:
Ttotal=294 minutes+150 minutes=444 minutes

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