Based on the alphabetical order, three of the following four are alike in a certain way and thus form a group. Which one does not belong to that group? (Note: The odd one out is not based on the number of consonants or vowels or their position in the letter cluster)
Correct Answer :
KMG
Solution :
The correct option is KMG.
To determine which letter cluster does not belong to the group, let us analyze the alphabetical positions of each letter in the given options.
Let us write down the numerical position of each letter in the English alphabet (where A = 1, B = 2, ..., Z = 26):
U = 21, W = 23, R = 18
S = 19, U = 21, P = 16
K = 11, M = 13, G = 7
E = 5, G = 7, B = 2
Now, let us find the pattern connecting the letters in each cluster:
1. UWR:
1st letter to 2nd letter: U (21) + 2 = W (23)
2nd letter to 3rd letter: W (23) - 5 = R (18)
2. SUP:
1st letter to 2nd letter: S (19) + 2 = U (21)
2nd letter to 3rd letter: U (21) - 5 = P (16)
3. EGB:
1st letter to 2nd letter: E (5) + 2 = G (7)
2nd letter to 3rd letter: G (7) - 5 = B (2)
4. KMG:
1st letter to 2nd letter: K (11) + 2 = M (13)
2nd letter to 3rd letter: M (13) - 6 = G (7)
As we can see, three of the clusters (UWR, SUP, EGB) follow the pattern (+2, -5), whereas KMG follows the pattern (+2, -6).
Therefore, KMG is the odd one out and does not belong to the group.
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