Based on the English alphabetical order, three of the following four are alike in a certain way and thus form a group. Which is the one that does not belong to that group?

(Note: The odd one out is not based on the number of consonants/vowels or their position in the letter cluster.)51

The correct option is DZV.

To determine which letter cluster does not belong to the group, let us analyze the pattern based on the positions of the letters in the English alphabet (where A = 1, B = 2, ..., Z = 26):

1. BXS:
Positions: B = 2, X = 24, S = 19
Difference between 1st and 2nd letter: B (2) to X (24) is -4 (moving backward: B → A → Z → Y → X)
Difference between 2nd and 3rd letter: X (24) to S (19) is -5 (24 - 5 = 19)

2. PLG:
Positions: P = 16, L = 12, G = 7
Difference between 1st and 2nd letter: P (16) to L (12) is -4 (16 - 4 = 12)
Difference between 2nd and 3rd letter: L (12) to G (7) is -5 (12 - 5 = 7)

3. WSN:
Positions: W = 23, S = 19, N = 14
Difference between 1st and 2nd letter: W (23) to S (19) is -4 (23 - 4 = 19)
Difference between 2nd and 3rd letter: S (19) to N (14) is -5 (19 - 5 = 14)

4. DZV:
Positions: D = 4, Z = 26, V = 22
Difference between 1st and 2nd letter: D (4) to Z (26) is -4 (moving backward: D → C → B → A → Z)
Difference between 2nd and 3rd letter: Z (26) to V (22) is -4 (26 - 4 = 22)

All options except DZV follow the pattern of subtracting 4 for the second letter and subtracting 5 for the third letter (-4, -5). In contrast, DZV follows a pattern of (-4, -4). Therefore, DZV is the odd one out.