Certain 3-digit numbers have the following characteristics:
1. All the three digits are different.
2. The number is divisible by 7.
3. The number on reversing the digits is also divisible by 7.
How many such 3-digit numbers are there?
Correct Answer :
4
Solution :
The correct answer is 4.
To find the total number of such 3-digit numbers, let us denote the number as:
where , , and are distinct single digits, and and (since reversing the number must also produce a valid 3-digit number).
The number obtained by reversing the digits is:
Step 1: Use divisibility by 7
According to the question, both and are divisible by 7. Therefore, their difference must also be divisible by 7.
Since 99 is not divisible by 7, the term must be a multiple of 7.
Step 2: Find possible values of and
Since and are non-zero single digits () and , the absolute difference can only be 7.
This gives two possible pairs for and their reverse counterparts:
1. or
2. or
Step 3: Test each pair to find digit
Case 1: and
The number is .
Dividing 801 by 7 leaves a remainder of 3 ().
For to be divisible by 7, (or ) must be divisible by 7.
Testing single-digit values of :
If , then , which is divisible by 7 ().
Since all digits (8, 6, 1) are distinct, 861 and its reverse 168 are valid numbers.
Case 2: and
The number is .
Dividing 902 by 7 leaves a remainder of 6 ().
For to be divisible by 7, (or ) must be divisible by 7.
Testing single-digit values of :
If , then , which is divisible by 7 ().
Since all digits (9, 5, 2) are distinct, 952 and its reverse 259 are valid numbers.
Conclusion:
The valid 3-digit numbers satisfying all given conditions are 168, 259, 861, and 952.
Thus, there are 4 such 3-digit numbers in total.
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