Choose the correct option for the total pressure (in atm.) in a mixture of 4 g O2 and 2 g H2 confined in a total volume of one litre at 0°C is : [Given R = 0.082 L atm mol−1K−1, T = 273 K]
Correct Answer :
25.18
Solution :
**Step 1 – Identify the given data**
Mass of O2 = 4 g
Mass of H2 = 2 g
Total volume V = 1 L
Temperature T = 0 °C = 273 K
Ideal‑gas constant R = 0.082 L atm mol−1K−1
**Step 2 – Convert the masses to moles**
Molar mass of O2 = 32 g mol−1 → n(O2) = 4 g / 32 g mol−1 = 0.125 mol
Molar mass of H2 = 2 g mol−1 → n(H2) = 2 g / 2 g mol−1 = 1 mol
**Step 3 – Find the total number of moles in the mixture**
n_total = n(O2) + n(H2) = 0.125 mol + 1 mol = 1.125 mol
**Step 4 – Apply the ideal‑gas equation**
Insert the known values:
**Step 5 – Perform the calculation**
First compute R T: 0.082 × 273 = 22.386
Then multiply by n_total: 22.386 × 1.125 = 25.18425 ≈ 25.18
**Result**
The total pressure of the gas mixture is **25.18 atm**.
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