Choose the correct option to solve the problem.
An investor has a total of Rs. 40000. He allocates a portion of this sum to Account A, which yields 30% per annum simple interest, and the remainder to Account B, which earns 20% interest compounded annually. If, after three years, the total interest generated from Account A is Rs. 9952 more than the interest accrued from Account B, find the sum invested in Account B.
Correct Answer :
Rs.16000
Solution :
The correct option is Rs.16000.
Step 1: Understand the given information and define the variables.
Total sum invested = Rs. 40000.
Let the sum invested in Account B be .
Therefore, the sum invested in Account A is .
Step 2: Calculate the Simple Interest earned from Account A.
Account A offers a 30% per annum simple interest for a period of 3 years.
The formula for Simple Interest is:
Substituting the values for Account A:
Step 3: Calculate the Compound Interest earned from Account B.
Account B earns 20% interest compounded annually for 3 years.
The formula for the total amount under Compound Interest is:
Substituting the values for Account B:
The Compound Interest is calculated by subtracting the principal from the total amount:
Step 4: Set up the equation and solve for .
We are given that the interest generated from Account A is Rs. 9952 more than the interest accrued from Account B:
Substitute the expressions obtained in Step 2 and Step 3:
Hence, the sum invested in Account B is Rs. 16000.
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