Consider a string P of length l that is laid out as a straight line segment. Another string K is laid out as a semi-circular arc with string P as diameter, (figure 1). When both the strings are shortened by a length of x they can be re-arranged such that the shortened string K forms a full circle with the shortened string P as diameter (figure 2). The value of x/l is _____.
Correct Answer :
π/2(π-1)
Solution :
The correct option is π/2(π-1).
Step 1: Understand the initial setup from Figure 1
From Figure 1, we observe two strings:
1. String P is a straight line segment of length that acts as the diameter of the semi-circle.
2. String K is laid out as a semi-circular arc with String P as its diameter.
The length of a semi-circular arc with diameter is given by half the circumference of a full circle of diameter . Therefore, the initial length of String K is:
Step 2: Express the lengths after shortening
Both strings are shortened by a length of .
- The new length of String P becomes:
- The new length of String K becomes:
Step 3: Relate the shortened strings using Figure 2
From Figure 2, after shortening, the shortened String K forms a full circle, and the shortened String P forms the diameter of this new circle.
The circumference of a circle with diameter is given by . Since the new diameter is and the circumference is , we have:
Substituting the expressions for the shortened lengths into this equation:
Step 4: Solve for the ratio x/l
First, expand the right-hand side of the equation:
Rearrange the terms to group all terms containing on the left-hand side and all terms containing on the right-hand side:
Factor out on the left side and simplify the right side:
To find the value of , divide both sides by :
This matches the provided correct answer.
Access expert-curated educational resources and study materials—completely free.
Create, conduct, and manage professional online assessments with Mindyard. Perfect for teachers and institutes.
Copyright © 2026 Mindyard. All Rights Reserved.