Question Details

Consider a string P of length l that is laid out as a straight line segment. Another string K is laid out as a semi-circular arc with string P as diameter, (figure 1). When both the strings are shortened by a length of x they can be re-arranged such that the shortened string K forms a full circle with the shortened string P as diameter (figure 2). The value of x/l is _____.


Options

A

π/2(π-1)

B

π

C

π/(π-1)

D

π-l/2π

Show Answer

Correct Answer :

Option A

π/2(π-1)

Solution :

The correct option is π/2(π-1).

Step 1: Understand the initial setup from Figure 1
From Figure 1, we observe two strings:
1. String P is a straight line segment of length l that acts as the diameter of the semi-circle.
2. String K is laid out as a semi-circular arc with String P as its diameter.
The length of a semi-circular arc with diameter l is given by half the circumference of a full circle of diameter l. Therefore, the initial length of String K is:

LK=πl2

Step 2: Express the lengths after shortening
Both strings are shortened by a length of x.
- The new length of String P becomes:

LP, new=l-x

- The new length of String K becomes:

LK, new=πl2-x

Step 3: Relate the shortened strings using Figure 2
From Figure 2, after shortening, the shortened String K forms a full circle, and the shortened String P forms the diameter of this new circle.
The circumference of a circle with diameter D is given by πD. Since the new diameter is LP, new and the circumference is LK, new, we have:

LK, new=π·LP, new

Substituting the expressions for the shortened lengths into this equation:

πl2-x=π(l-x)

Step 4: Solve for the ratio x/l
First, expand the right-hand side of the equation:

πl2-x=πl-πx

Rearrange the terms to group all terms containing x on the left-hand side and all terms containing l on the right-hand side:

πx-x=πl-πl2

Factor out x on the left side and simplify the right side:

x(π-1)=πl2

To find the value of xl, divide both sides by l(π-1):

xl=π2(π-1)

This matches the provided correct answer.

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