Question Details

Consider the following multiplication problem:

(PQ) × 3 = RQQ, where P, Q and R are different digits and R ≠ 0.

What is the value of (P + R) ÷ Q?

Options

A

1

B

2

C

3

D

Cannot be determined due to insufficient data

Show Answer

Correct Answer :

Option B

2

Solution :

The correct option is 2.

Step-by-step Explanation:

We are given the multiplication equation:

(PQ)×3=RQQ

where P, Q, and R are distinct single digits and R0.

Let's represent the numbers in expanded decimal form:
PQ=10P+Q
RQQ=100R+10Q+Q=100R+11Q

Substituting these expressions into the given multiplication problem:

3×(10P+Q)=100R+11Q

30P+3Q=100R+11Q

Subtracting 3Q from both sides:

30P=100R+8Q

Dividing the entire equation by 2:

15P=50R+4Q

Since 15P and 50R are both divisible by 5, the term 4Q must also be divisible by 5. Since Q is a single digit (0 through 9), Q must be either 0 or 5.

Case 1: If Q=0
15P=50R3P=10R
Since P9, 3P27, which means 10R cannot exceed 27. The only possibilities for R would be 1 or 2, but neither yields an integer value for P. Thus, Q0.

Case 2: If Q=5
Substitute Q=5 into the simplified equation:
15P=50R+4(5)
15P=50R+20
Dividing by 5 gives:
3P=10R+4

Testing integer values for R (since R0):
If R=1: 3P=14 (not an integer).
If R=2: 3P=24P=8.

So, we find:
P=8
Q=5
R=2

Checking the multiplication:
85×3=255
All digits P,Q,R (8, 5, 2) are different, and R0.

Now, calculate the value of (P+R)÷Q:

(P+R)÷Q=(8+2)÷5=10÷5=2

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