Question Details

Consider the four-variable Boolean function, f(w, x, y, z) = Σm(0, 2, 5, 7, 8, 10, 13, 14, 15) with w as MSB and z as LSB. Which of the following expressions is/are the valid form(s) of f(w, x, y, z)?

Options

A

x ¯ z ¯ + xz + wxy

B

xz + wxy + w x ¯ z ¯ + w ¯ xy z ¯

C

x ¯ z ¯ + wxy + w x ¯ z ¯ + w ¯ xy z ¯

D

x ¯ z ¯ + xz + wy z ¯

Show Answer

Correct Answer :

Option A

x ¯ z ¯ + xz + wxy

Option D

x ¯ z ¯ + xz + wy z ¯

Solution :

The correct options are:
1. x ¯ z ¯ + xz + wxy
2. x ¯ z ¯ + xz + wy z ¯

To determine which expressions are valid forms of the Boolean function f(w,x,y,z)=Σm(0,2,5,7,8,10,13,14,15), we can analyze the minterms using a Karnaugh map (K-map).

Let us represent the 4-variable K-map with wx along the rows and yz along the columns:
- Rows: w¯x¯ (00), w¯x (01), wx (11), wx¯ (10)
- Columns: y¯z¯ (00), y¯z (01), yz (11), yz¯ (10)

The minterm numbers correspond to the K-map cells as follows:
- Row 00: m0 (0000), m1 (0001), m3 (0011), m2 (0010)
- Row 01: m4 (0100), m5 (0101), m7 (0111), m6 (0110)
- Row 11: m12 (1100), m13 (1101), m15 (1111), m14 (1110)
- Row 10: m8 (1000), m9 (1001), m11 (1011), m10 (1010)

Placing 1s in the cells corresponding to the given minterms: {0, 2, 5, 7, 8, 10, 13, 14, 15}, we get:
- Row 00 (w¯x¯): 1 at col 00 (m0), 1 at col 10 (m2)
- Row 01 (w¯x): 1 at col 01 (m5), 1 at col 11 (m7)
- Row 11 (wx): 1 at col 01 (m13), 1 at col 11 (m15), 1 at col 10 (m14)
- Row 10 (wx¯): 1 at col 00 (m8), 1 at col 10 (m10)

Let us group the cells to find the prime implicants:
1. Grouping the four corners: m0, m2, m8, m10. This quad gives the term:
x ¯ z ¯
2. Grouping the quad in the columns with z=1: m5, m7, m13, m15. This quad gives the term:
xz

After these two groups, the only remaining uncovered minterm is m14 (1110).
We can cover m14 using one of two possible groups:
- Grouping m14 with m15 (1111): The group is {m14, m15}, which corresponds to row 11 (wx) and columns 11 and 10 (y). This yields the term:
wxy
- Grouping m14 with m10 (1010): The group is {m10, m14}, which corresponds to rows 11 and 10 (w) and column 10 (yz¯). This yields the term:
wy z ¯

Combining these groups gives two valid minimal sum-of-products (SOP) expressions for f:
1. f= x ¯ z ¯ + xz + wxy
2. f= x ¯ z ¯ + xz + wy z ¯

Both of these expressions are minimal SOP forms and represent valid forms of f(w,x,y,z).

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