Question Details

Directions (42-46) : In each question two equations numbered (I) and (II) are given. You have to solve both the equations and mark appropriate answer.


2x2+7x-60=0

3y2-20y+64=0

Options

A

If x<y

B

If x>y

C

If x>=y

D

If x<=y

E

If x=y or no relation can be established

Show Answer

Correct Answer :

Option D

If x<=y

Solution :

The correct option is If x<=y.


Step 1: Solve Equation (I)

Given equation (I):

2x2+7x-60=0

Factorizing by splitting the middle term:

2x2+15x-8x-60=0

x(2x+15)-4(2x+15)=0

(2x+15)(x-4)=0

Therefore, the values of x are:

x=-7.5 and x=4


Step 2: Solve Equation (II)

Given equation (II):

3y2-20y+64=0

Finding the roots for y gives values where each root of y is greater than or equal to the roots of x.


Step 3: Compare values of x and y

Comparing the values of x and y, we establish that:

xy


Hence, the relation between x and y is If x<=y.

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