Question Details

Directions (74-78): Study the information carefully and answer the questions given below.

Ten persons were born in five different months of the same year starting from August to December, but on two different dates, i.e., 10th and 15th. K was born in the month which has odd number of days. Six persons were born in between K and D who was born after K. D was not born in the last. Two persons were born between D and S. The number of persons born before S is same as the number of persons born after G. R was born on an even number date and the month which has even number of days. Five persons were born between R and F who was born in the same month as P. Z was born before V but after H.


Four of the following five are alike in a certain way so form a group, which of the following does not belong to that group?

Options

A

R

B

H

C

G

D

D

Show Answer

Correct Answer :

Option A

R

Solution :

The correct option is R.


Step-by-Step Explanation:


1. Understand the given schedule:

There are 5 months: August (31 days), September (30 days), October (31 days), November (30 days), and December (31 days).

Each month has two dates: 10th and 15th, making 10 total slots in chronological order:

1. August 10th (Odd number of days, Even date)

2. August 15th (Odd number of days, Odd date)

3. September 10th (Even number of days, Even date)

4. September 15th (Even number of days, Odd date)

5. October 10th (Odd number of days, Even date)

6. October 15th (Odd number of days, Odd date)

7. November 10th (Even number of days, Even date)

8. November 15th (Even number of days, Odd date)

9. December 10th (Odd number of days, Even date)

10. December 15th (Odd number of days, Odd date)


2. Place K, D, S, and G:

• K was born in a month with an odd number of days (August, October, or December).

• Six persons were born between K and D, and D was born after K.

• If K is at Slot 1 (August 10th), then 6 persons are between K and D, which puts D at Slot 8 (November 15th).

• If K is at Slot 2 (August 15th), D would be at Slot 9 (December 10th). But D was not born in the last month (December). Therefore, K must be born on August 10th (Slot 1) and D is born on November 15th (Slot 8).

• Two persons were born between D (Slot 8) and S. Counting upwards, S is at Slot 5 (October 10th).

• The number of persons born before S is 4 (Slots 1 to 4). Thus, the number of persons born after G must also be 4. This places G at Slot 6 (October 15th).


3. Place R, F, and P:

• R was born on an even date (10th) and in a month with an even number of days (September or November). The 10th of September is Slot 3, and the 10th of November is Slot 7.

• Five persons were born between R and F. If R is at Slot 3 (September 10th), F is at Slot 9 (December 10th). (If R were at Slot 7, F would be at Slot 1, but Slot 1 is already K).

• Thus, R is at Slot 3 (September 10th) and F is at Slot 9 (December 10th).

• F was born in the same month as P (December). Since F is on December 10th, P must be on December 15th (Slot 10).


4. Place H, Z, and V:

• The remaining vacant slots are Slot 2 (August 15th), Slot 4 (September 15th), and Slot 7 (November 10th).

• Z was born before V but after H (Order: H ... Z ... V).

• Therefore: H = Slot 2 (August 15th), Z = Slot 4 (September 15th), V = Slot 7 (November 10th).


Final Arrangement:

1. August 10th: K

2. August 15th: H

3. September 10th: R

4. September 15th: Z

5. October 10th: S

6. October 15th: G

7. November 10th: V

8. November 15th: D

9. December 10th: F

10. December 15th: P


5. Determine the odd one out:

• H (August 15th) is born on an odd date (15th).

• G (October 15th) is born on an odd date (15th).

• D (November 15th) is born on an odd date (15th).

• R (September 10th) is born on an even date (10th).


Since R is the only one born on an even date (10th) while the others are born on odd dates (15th), R does not belong to the group.

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