Directions (75-79): Read the given number series carefully to answer the related questions:

692    318    196     486 7   54

If we remove even digits from each number in the series than how many prime numbers formed?

Let's analyze the given number series step-by-step to find the solution.

The given number series is:
692    318    196    486    754

The question asks us to remove the even digits (i.e., 2, 4, 6, 8) from each number in the series and find out how many prime numbers are formed as a result.

Let's process each number in the series individually:

1. First number: 692
- The digits are 6 (even), 9 (odd), and 2 (even).
- Removing the even digits (6 and 2) leaves us with: 9.
- Let's check if 9 is prime: 9 is divisible by 3 ($3\times 3=9$), so it is not a prime number.

2. Second number: 318
- The digits are 3 (odd), 1 (odd), and 8 (even).
- Removing the even digit (8) leaves us with: 31.
- Let's check if 31 is prime: 31 has no factors other than 1 and itself, so 31 is a prime number.

3. Third number: 196
- The digits are 1 (odd), 9 (odd), and 6 (even).
- Removing the even digit (6) leaves us with: 19.
- Let's check if 19 is prime: 19 has no factors other than 1 and itself, so 19 is a prime number.

4. Fourth number: 486
- The digits are 4 (even), 8 (even), and 6 (even).
- Removing all the even digits (4, 8, and 6) leaves us with no digits (empty/no number formed).

5. Fifth number: 754
- The digits are 7 (odd), 5 (odd), and 4 (even).
- Removing the even digit (4) leaves us with: 75.
- Let's check if 75 is prime: 75 is divisible by 3 and 5 ($15\times 5=75$), so it is not a prime number.

Comparing the numbers formed after removing the even digits:
- From 692: 9 (Not Prime)
- From 318: 31 (Prime)
- From 196: 19 (Prime)
- From 486: None
- From 754: 75 (Not Prime)

Thus, the prime numbers formed are 31 and 19. A total of two prime numbers are formed.

Therefore, the correct answer is Two.