Directions (75-79): Read the given number series carefully to answer the related questions:

692    318    196     486 7   54

What is the difference between 2nd digit of highest number and 3rd digit of 4th lowest number?

Let's write down the given number series carefully:
692   318   196   486   754

(Note: The series numbers are 692, 318, 196, 486, and 754.)

Step 1: Find the highest number.
Comparing the numbers: 196 < 318 < 486 < 692 < 754.
The highest number in the series is 754.
The digits of 754 from left to right are:
1st digit = 7
2nd digit = 5
3rd digit = 4
So, the 2nd digit of the highest number is 5.

Step 2: Find the 4th lowest number.
Let's arrange the numbers in ascending order (from lowest to highest):
1st lowest = 196
2nd lowest = 318
3rd lowest = 486
4th lowest = 692
5th lowest = 754
Thus, the 4th lowest number in the series is 692.
The digits of 692 from left to right are:
1st digit = 6
2nd digit = 9
3rd digit = 2
So, the 3rd digit of the 4th lowest number is 2.

Step 3: Calculate the difference between these two digits.
We need to find:
Difference = (2nd digit of highest number) - (3rd digit of 4th lowest number)
$\mathrm{Difference}=5-2=3$

Therefore, the required difference is 3.