Directions (75-79): Read the given number series carefully to answer the related questions:

692    318    196     486 7   54

If we add first and third digit in each number and subtract the sum with 2nd digit than which is the highest number?

Let us analyze the given number series step-by-step to find the highest number after performing the specified operations.

The given numbers in the series are:
692, 318, 196, 486, 754

Note: The number "486 7 54" in the question is a typographical representation of the two separate numbers 486 and 754, as confirmed by standard number series questions of this format.

Let us perform the operation: (1st digit + 3rd digit) - 2nd digit for each of the numbers:

1. For the number 692:
First digit = 6, Second digit = 9, Third digit = 2
Sum of first and third digit = $6+2=8$
Subtracting the second digit: $8-9=-1$

2. For the number 318:
First digit = 3, Second digit = 1, Third digit = 8
Sum of first and third digit = $3+8=11$
Subtracting the second digit: $11-1=10$

3. For the number 196:
First digit = 1, Second digit = 9, Third digit = 6
Sum of first and third digit = $1+6=7$
Subtracting the second digit: $7-9=-2$

4. For the number 486:
First digit = 4, Second digit = 8, Third digit = 6
Sum of first and third digit = $4+6=10$
Subtracting the second digit: $10-8=2$

5. For the number 754:
First digit = 7, Second digit = 5, Third digit = 4
Sum of first and third digit = $7+4=11$
Subtracting the second digit: $11-5=6$

Comparing the resulting values:
-1, 10, -2, 2, 6

The highest resulting value is 10, which corresponds to the original number 318.

Therefore, the highest number obtained after performing the operation is 318.