Directions (75-79): Read the given number series carefully to answer the related questions:

692    318    196     486 7   54

If we add first and third digit in each number and subtract the sum with 2nd digit than which is the highest number?

To find the highest number after performing the specified operation, let us first identify the given number series.
The numbers are: 692, 318, 196, 486, and 754.

For each number, the question asks us to:
1. Add the first and third digits.
2. Subtract the second digit from this sum.

Let's perform these steps for each number:

For 692:
First digit = 6, Second digit = 9, Third digit = 2
Sum of first and third digit = $6+2=8$
Subtracting the second digit: $8-9=-1$

For 318:
First digit = 3, Second digit = 1, Third digit = 8
Sum of first and third digit = $3+8=11$
Subtracting the second digit: $11-1=10$

For 196:
First digit = 1, Second digit = 9, Third digit = 6
Sum of first and third digit = $1+6=7$
Subtracting the second digit: $7-9=-2$

For 486:
First digit = 4, Second digit = 8, Third digit = 6
Sum of first and third digit = $4+6=10$
Subtracting the second digit: $10-8=2$

For 754:
First digit = 7, Second digit = 5, Third digit = 4
Sum of first and third digit = $7+4=11$
Subtracting the second digit: $11-5=6$

Comparing the final values obtained for each number:
692: -1
318: 10
196: -2
486: 2
754: 6

The highest resulting value is 10, which corresponds to the original number 318.

Therefore, the correct answer is 318.