Directions (96-100) : Study the following information carefully and answer the questions given below.
Seven persons go to Shimla on seven different days from Monday to Sunday. Two persons go between A and B who goes after Thursday. C goes just before A. The number of persons goes before C is one less than the number of persons goes after D. G goes three persons before F and goes after E. At least one person goes before E.
Who among the following persons goes on Wednesday?
Correct Answer :
E
Solution :
The correct answer is E.
Let's solve the puzzle step-by-step to determine the schedule of the seven persons from Monday to Sunday.
Step 1: Understand the given clues
1. The seven days are Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, and Sunday.
2. B goes after Thursday, which means B goes on either Friday, Saturday, or Sunday.
3. Two persons go between A and B.
4. C goes just before A.
5. The number of persons going before C is one less than the number of persons going after D.
6. G goes three persons before F (meaning G is 3 positions above F: G _ _ F).
7. G goes after E (E goes before G).
8. At least one person goes before E (E cannot go on Monday).
Step 2: Determine the positions of B, A, and C
Since B goes after Thursday, let's test the possible days for B:
Case 1: If B goes on Friday
Two persons go between A and B, so A must go on Tuesday.
C goes just before A, which means C goes on Monday.
Number of persons before C = 0.
According to the clue, 0 is one less than the number of persons after D, so the number of persons after D must be 1.
Therefore, D goes on Saturday.
Now, let's place E, G, and F in the remaining vacant days (Wednesday, Thursday, Sunday):
G goes three persons before F. The available days for G and F with a gap of 2 days between them would be Wednesday and Saturday, but Saturday is already occupied by D. Thus, Case 1 fails.
Case 2: If B goes on Saturday
Two persons go between A and B, so A must go on Wednesday.
C goes just before A, which means C goes on Tuesday.
Number of persons before C = 1 (Monday).
So, the number of persons after D must be 2 (since 1 is one less than 2).
Therefore, D goes on Friday (persons after D would be Saturday and Sunday).
Let's check the remaining vacant days for Case 2: Monday, Thursday, Sunday.
G goes three persons before F (G _ _ F). The only suitable gap of 3 steps is Thursday to Sunday. So, G goes on Thursday and F goes on Sunday.
Now, the only remaining day for E is Monday.
However, the clue states that "G goes after E" (satisfied, since E is Monday and G is Thursday) and "At least one person goes before E". Since E is on Monday, zero persons go before E, which violates the condition "At least one person goes before E". Thus, Case 2 fails.
Case 3: If B goes on Sunday
Two persons go between A and B, so A must go on Thursday.
C goes just before A, which means C goes on Wednesday.
Number of persons before C = 2 (Monday, Tuesday).
So, the number of persons after D must be 3 (since 2 is one less than 3).
Therefore, D goes on Thursday, but Thursday is already occupied by A. So this placement needs careful verification:
Wait, let's re-verify the remaining slots for Case 3:
Days: Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday.
If B = Sunday:
Two persons between A and B ⇒ A = Thursday.
C just before A ⇒ C = Wednesday.
Persons before C = 2 (Mon, Tue).
Number of persons after D = 3 ⇒ D must be on Thursday. But Thursday is A! So D cannot be Thursday. Let's re-evaluate the clues for placing G, F, E, D, C, A, B.
Let's re-check Case 2 with B on Friday, Saturday, Sunday, or other arrangements:
Let's list all possible placements of C, A, B:
Since C is just before A (C, A), and 2 persons are between A and B (A _ _ B or B _ _ A):
- If B is Friday: C(Mon), A(Tue), B(Fri). Before C = 0. After D = 1 ⇒ D(Sat). Vacant: Wed, Thu, Sun. G _ _ F requires G(Wed), F(Sat), but Sat is D. Or G(Thu), F(Sun). Then E(Wed).
Let's check if G(Thu), F(Sun), E(Wed) works in Case 1!
Let's test this schedule:
Monday: C
Tuesday: A
Wednesday: E
Thursday: G
Friday: B
Saturday: D
Sunday: F
Step 3: Verify all conditions with this schedule:
1. B goes after Thursday: B goes on Friday (Valid).
2. Two persons between A and B: A (Tuesday) and B (Friday) have Wednesday and Thursday between them (Valid).
3. C goes just before A: C is Monday, A is Tuesday (Valid).
4. Number of persons before C is 0. Number of persons after D (Saturday) is 1 (Sunday). 0 is one less than 1 (Valid).
5. G goes three persons before F: G is Thursday, F is Sunday (Thursday → Friday → Saturday → Sunday, G is 3 days before F) (Valid).
6. G goes after E: E is Wednesday, G is Thursday (Valid).
7. At least one person goes before E: C goes on Monday, so 2 persons (C, A) go before E (Valid).
Final Schedule:
• Monday: C
• Tuesday: A
• Wednesday: E
• Thursday: G
• Friday: B
• Saturday: D
• Sunday: F
Therefore, E goes to Shimla on Wednesday.
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