Directions (96-100): Study the given series of numbers, symbols and alphabets and answer the questions based on it.

2 F T % 4 Y 8 $ B 9 P M 6 # 7 V A Ω 5 I E ∞ J 9 I β 6 N 4 ϕ L K 3 µ

If the symbols are dropped from the given series then which among the following element is 3rd to the left of 2nd even number from right end?

The correct option is J.

To find the correct element, we can follow these step-by-step logic and calculations:
1. Analyze the original series:
The given series is:
2 F T % 4 Y 8 $ B 9 P M 6 # 7 V A Ω 5 I E ∞ J 9 I β 6 N 4 ϕ L K 3 µ

2. Drop all symbols from the series:
The symbols in the series are %, $, #, Ω, ∞, β, ϕ, and µ. Removing these symbols gives the new series:
2 F T 4 Y 8 B 9 P M 6 7 V A 5 I E J 9 I 6 N 4 L K 3

3. Locate the 2nd even number from the right end of the new series:
Scanning the series from the right end (starting at 3):
- 3 (odd number)
- K (letter)
- L (letter)
- 4 (1st even number from the right)
- N (letter)
- 6 (2nd even number from the right)
Thus, the 2nd even number from the right end is 6.

4. Find the element 3rd to the left of 6:
Looking at the elements to the left of 6 in the modified series:
- 1st to the left of 6 is I.
- 2nd to the left of 6 is 9.
- 3rd to the left of 6 is J.
Therefore, the element is J.