Directions (96-100): Study the given series of numbers, symbols and alphabets and answer the questions based on it.

2 F T % 4 Y 8 $ B 9 P M 6 # 7 V A Ω 5 I E ∞ J 9 I β 6 N 4 ϕ L K 3 µ

If the symbols are dropped from the given series then which among the following element is 3rd to the left of 2nd even number from right end?

The correct option is J.

Let's find the solution step-by-step:

Step 1: Write down the original series:
2 F T % 4 Y 8 $ B 9 P M 6 # 7 V A Ω 5 I E ∞ J 9 I β 6 N 4 ϕ L K 3 µ

Step 2: Drop all the symbols from the series:
The symbols present in the series are: %, $, #, Ω, ∞, β, ϕ, and ��.
Removing these symbols, the new series becomes:
2 F T 4 Y 8 B 9 P M 6 7 V A 5 I E J 9 I 6 N 4 L K 3

Step 3: Identify the even numbers from the right end of the new series:
Looking at the series from the right end (3, K, L, 4, N, 6, I, 9, J...):
- The first number we encounter is 3, which is odd.
- The next number is 4, which is the 1st even number from the right end.
- The next number is 6, which is the 2nd even number from the right end.

Step 4: Find the element that is 3rd to the left of the 2nd even number (6):
In the modified series, the elements to the left of 6 are:
... J 9 I 6 ...
- 1st to the left of 6 is I.
- 2nd to the left of 6 is 9.
- 3rd to the left of 6 is J.

Therefore, the element that is 3rd to the left of the 2nd even number from the right end is J.