Directions: The following questions are based on five three digit numbers given below:
453       619       574       471       372
If in each number, all the three digits are arranged in ascending order within the number, which of the following will be the second lowest number after rearrangement?

The correct option is 619.

Step-by-step Explanation:

Step 1: Understand the given set of numbers

We are given the following five three-digit numbers:

453, 619, 574, 471, 372

Step 2: Rearrange the digits of each number in ascending order

Arranging the digits of each individual number from smallest to largest:

• For 453: The digits are 4, 5, and 3. Arranged in ascending order, we get 345.
• For 619: The digits are 6, 1, and 9. Arranged in ascending order, we get 169.
• For 574: The digits are 5, 7, and 4. Arranged in ascending order, we get 457.
• For 471: The digits are 4, 7, and 1. Arranged in ascending order, we get 147.
• For 372: The digits are 3, 7, and 2. Arranged in ascending order, we get 237.

Step 3: Compare the newly formed numbers

The new set of numbers obtained after rearrangement is:

147, 169, 237, 345, 457

Step 4: Identify the second lowest number

Let's arrange these new numbers from lowest to highest:

1. Lowest number = 147 (originally 471)
2. Second lowest number = 169 (originally 619)

Therefore, the original number that corresponds to the second lowest number after rearrangement is 619.