Choose the correct option to solve the problem.
An investor has a total of Rs. 40000. He allocates a portion of this sum to Account A, which yields 30% per annum simple interest, and the remainder to Account B, which earns 20% interest compounded annually. If, after three years, the total interest generated from Account A is Rs. 9952 more than the interest accrued from Account B, find the sum invested in Account B.
Correct Answer :
Rs.16000
Solution :
The correct option is Rs.16000.
Step-by-Step Explanation:
1. Define the Variables:
Let the total sum available for investment be Rs. 40,000.
Let the sum invested in Account B be .
Therefore, the remaining sum invested in Account A is .
2. Calculate Simple Interest from Account A:
Account A offers simple interest at a rate of 30% per annum for 3 years.
The formula for Simple Interest (SI) is:
Substituting the values for Account A:
Principal () =
Rate () = 30% per annum
Time () = 3 years
3. Calculate Compound Interest from Account B:
Account B yields interest at 20% per annum compounded annually for 3 years.
The formula for Compound Interest (CI) is:
Substituting the values for Account B:
Principal () =
Rate () = 20%
Time () = 3 years
4. Set up and Solve the Equation:
The problem states that the interest accrued from Account A is Rs. 9952 more than the interest accrued from Account B:
Substituting the expressions derived for SI and CI:
Therefore, the sum invested in Account B is Rs. 16000.
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