Eight persons A, B, C, D, E, F, G, and H live on different floors of an eight-floor building, numbered 1 to 8 from bottom to top. One person lives on each floor but not necessarily in the given order.

G lives five floors above C. As many floors are there below C’s floor as above B’s floor. Three floors are there between the floors of B and D. F lives two floors away D. E does not live above H. A doesn’t live on prime numbered floor.

Who lives three floors above the floor on which A lives?

To find who lives three floors above A, we can construct the floor-by-floor arrangement step-by-step using the given clues.

Let the floors be numbered 1 to 8 from bottom to top.

Step 1: Determine the positions of G and C
G lives five floors above C. This means:
$\mathrm{Floor\; of\; G}=\mathrm{Floor\; of\; C}+5$
Since there are only 8 floors, the floor of C can only be 1, 2, or 3. Thus, the possible pairs for (C, G) are:
- If C lives on floor 1, G lives on floor 6.
- If C lives on floor 2, G lives on floor 7.
- If C lives on floor 3, G lives on floor 8.

Step 2: Determine the position of B
We are given that as many floors are below C's floor as above B's floor. The number of floors below floor C is:
$\mathrm{Floor\; of\; C}-1$
The number of floors above floor B is:
$8-\mathrm{Floor\; of\; B}$
Setting these equal gives:
$\mathrm{Floor\; of\; B}=9-\mathrm{Floor\; of\; C}$
Let us evaluate our three cases from Step 1:
- Case A: If C is on floor 1, then B is on floor 8 (9 - 1) and G is on floor 6.
- Case B: If C is on floor 2, then B is on floor 7 (9 - 2) and G is on floor 7. This is impossible because both B and G cannot live on floor 7.
- Case C: If C is on floor 3, then B is on floor 6 (9 - 3) and G is on floor 8.

We are left with two possible cases: Case A and Case C.

Step 3: Determine the positions of D and F
We are told that three floors are between B and D. This means:
$|\mathrm{Floor\; of\; B}-\mathrm{Floor\; of\; D}|=4$
Let's apply this to both remaining cases:
- In Case A (B = 8): D must be on floor 4.
- In Case C (B = 6): D must be on floor 2.
F lives two floors away from D. This means:
$|\mathrm{Floor\; of\; F}-\mathrm{Floor\; of\; D}|=2$
- In Case A (D = 4): F could be on floor 2 or 6. Since G is already on floor 6, F must be on floor 2.
- In Case C (D = 2): F could be on floor 4 (floor 0 does not exist). So F must be on floor 4.

Step 4: Place A, E, and H using the remaining clues
Let's list the occupied floors for both cases:
- Case A: Floor 1 (C), Floor 2 (F), Floor 4 (D), Floor 6 (G), Floor 8 (B) are occupied. The empty floors are 3, 5, and 7.
- Case C: Floor 2 (D), Floor 3 (C), Floor 4 (F), Floor 6 (B), Floor 8 (G) are occupied. The empty floors are 1, 5, and 7.

We are given that A does not live on a prime-numbered floor. The prime numbers up to 8 are 2, 3, 5, and 7.
- In Case A, the empty floors are 3, 5, and 7. Since all of these are prime numbers, A cannot be placed on any floor. Thus, Case A is eliminated.
- In Case C, the empty floors are 1, 5, and 7. Since 1 is not a prime number, A must live on floor 1.

Now, the remaining empty floors are 5 and 7. E does not live above H, which means E must live below H. Therefore, E lives on floor 5 and H lives on floor 7.

Final Floor Arrangement:
Floor 8: G
Floor 7: H
Floor 6: B
Floor 5: E
Floor 4: F
Floor 3: C
Floor 2: D
Floor 1: A

Conclusion:
A lives on floor 1. Three floors above the floor on which A lives is:
$1+3=4$
Floor 4 is occupied by F.