Question Details

Eight persons — A, B, C, D, E, F, G and H — were born on two different dates i.e. 11th and 20th of four different months viz. August, October, November and December of the same year. No two persons were born on the same day. G was born four persons before B. B was born in the month having even number of days. E was born two persons after G. A was born three persons before E. F was born in the month having even number of days. F was born after C. D was born on an odd number date.

Who among the following was born in 20th October?

Options

A

A

B

E

C

F

D

C

E

G

Show Answer

Correct Answer :

Option B

E

Solution :

The correct option is E.


Step-by-Step Explanation:


First, let us list the given dates and months in chronological order:

1. August 11 (31 days)
2. August 20 (31 days)
3. October 11 (31 days)
4. October 20 (31 days)
5. November 11 (30 days — even number of days)
6. November 20 (30 days — even number of days)
7. December 11 (31 days)
8. December 20 (31 days)


Now, let us analyze the conditions provided in the question:


1. "B was born in the month having even number of days."
The month with an even number of days (30 days) is November. So, B must be born on either November 11 or November 20.


2. "G was born four persons before B."
This means there are 3 persons born between G and B (G _ _ _ B):
- If B is born on November 11 (5th position), G must be born on August 11 (1st position).
- If B is born on November 20 (6th position), G must be born on August 20 (2nd position).


3. "E was born two persons after G."
This means E is born at position (Position of G + 2):
- Case 1: If G is on August 11 (1st position), E is on October 11 (3rd position).
- Case 2: If G is on August 20 (2nd position), E is on October 20 (4th position).


4. "A was born three persons before E."
This means A is born at position (Position of E − 3):
- In Case 1: Position of E is 3rd, so Position of A would be 3 − 3 = 0, which is invalid.
- In Case 2: Position of E is 4th (October 20), so Position of A is 4 − 3 = 1st (August 11). This is valid!


Thus, Case 2 is correct. Let's fix the positions determined so far:

- Position 1 (August 11): A
- Position 2 (August 20): G
- Position 4 (October 20): E
- Position 6 (November 20): B


5. "F was born in the month having even number of days" and "F was born after C".
The remaining positions in November (even month) is November 11 (Position 5). Hence, F must be born on November 11.


6. "D was born on an odd number date."
The remaining available positions are:
- Position 3 (October 11 — odd date)
- Position 7 (December 11 — odd date)
- Position 8 (December 20 — even date)
Since F was born after C, C must occupy Position 3 (October 11).
Since D was born on an odd number date, D must occupy Position 7 (December 11).
The remaining person H occupies Position 8 (December 20).


Final Arrangement:

- August 11: A
- August 20: G
- October 11: C
- October 20: E
- November 11: F
- November 20: B
- December 11: D
- December 20: H


Therefore, E was born on 20th October.

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