Find the sum of the difference between red balls and blue balls sold by A and red balls sold by B.

The data in the table shows the average number of items (Red and Blue balls) sold by five shops and percentage of red balls sold.

Shops	Average number of items (Red and blue balls) sold	Percentage of red balls sold
A	50	25%
B	30	20%
C	25	20%
D	25	54%
E	35	51$\frac{3}{7}$%

The correct answer is 62.

Here is the step-by-step explanation and derivation to solve the problem:

Step 1: Understand the given data
The table shows the average number of items (Red and Blue balls combined) sold by each shop, and the percentage of red balls sold. Since the two types of items are Red and Blue balls, the total number of balls sold by any shop is equal to:
$\text{Total balls sold}=\text{Average number of items}\times 2$

Step 2: Calculate the balls sold by Shop A
For Shop A, the average number of items sold is 50. Therefore, the total number of balls sold is:
$\text{Total balls sold by A}=50\times 2=100$

The percentage of red balls sold by A is 25%. So, the number of red balls sold is:
$\text{Red balls sold by A}=25\%\text{ of }100=25$

The number of blue balls sold by A is:
$\text{Blue balls sold by A}=100-25=75$

Now, calculate the absolute difference between the red balls and blue balls sold by A:
$\text{Difference for A}=75-25=50$

Step 3: Calculate the red balls sold by Shop B
For Shop B, the average number of items sold is 30. Therefore, the total number of balls sold is:
$\text{Total balls sold by B}=30\times 2=60$

The percentage of red balls sold by B is 20%. So, the number of red balls sold is:
$\text{Red balls sold by B}=20\%\text{ of }60=12$

Step 4: Find the required sum
We need to find the sum of the difference calculated for A and the red balls sold by B:
$\text{Required Sum}=50+12=62$