Question Details

Find the value of the angle of emergence from the prism. Refractive index of the glass is √ 3 .

Options

A

30°

B

45°

C

90°

D

60°

Show Answer

Correct Answer :

Option D

60°

60°

Solution :

The correct option/answer is 60°.

Based on the standard physics problem details and the accompanying diagram, we are given:
1. A glass prism with a prism angle (angle of the prism) of A=60°.
2. A light ray incident on the first refracting face of the prism at an angle of incidence i=60°.
3. The refractive index of the glass prism is μ=3 and the surrounding medium is air with a refractive index of μair=1.

To find the angle of emergence (e), we follow a step-by-step approach using Snell's Law and the geometry of a prism:

Step 1: Apply Snell's Law at the first refracting surface
Snell's Law at the first boundary (air-to-glass interface) is given by:
μair·sin(i)=μ·sin(r1)
where r1 is the angle of refraction inside the prism.

Substitute the given values into the equation:
1·sin(60°)=3·sin(r1)
Since sin(60°)=32, we have:
32=3·sin(r1)

Dividing both sides by 3:
sin(r1)=12
This gives the first refraction angle:
r1=30°

Step 2: Use prism geometry to find the angle of incidence at the second surface
For any prism, the relation between the prism angle A and the internal refraction angles r1 and r2 is:
A=r1+r2
Substitute A=60° and r1=30°:
60°=30°+r2
Solving for r2:
r2=30°

Step 3: Apply Snell's Law at the second refracting surface (glass-to-air interface)
Snell's Law at the boundary where the light ray emerges into the air is:
μ·sin(r2)=μair·sin(e)
Substitute the values into the equation:
3·sin(30°)=1·sin(e)
Since sin(30°)=12:
3·12=sin(e)
sin(e)=32

Taking the inverse sine of both sides:
e=60°

Thus, the value of the angle of emergence from the prism is 60°.

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