Five capacitors of capacitances C₁ = C₂ = C₃ = C₄ = 10µF and C₅ = 2.5µF are connected as shown, along with a battery of 50 V. The equivalent capacitance and the charges on each capacitor respectively are: ____.

The diagram supplied in the image shows the five capacitors connected to a 50 V battery as follows:

‑ Capacitors C₁, C₂, C₃ and C₄ (each 10 µF) are arranged **in series**.

‑ The series string is placed **in parallel** with capacitor C₅ (2.5 µF).

Thus the overall circuit consists of a series group of four equal capacitors and a single capacitor that shares the same terminals as that group.

**Step 1: Find the equivalent capacitance of the series group.**

Since C₁=C₂=C₃=C₄=10 µF,

**Step 2: Combine with C₅ in parallel.**

**Step 3: Determine the voltage across each branch.**

The series group and C₅ are in parallel, so they share the full battery voltage:

**Step 4: Find the charge on each capacitor.**

For the parallel capacitor C₅:

For the series capacitors (C₁–C₄):

In a series connection the charge on each capacitor is the same. The voltage across each of the four equal‑capacitance capacitors is one‑fourth of the total branch voltage:

Hence the charge on any C_i (i = 1…4) is

All five capacitors therefore store the same charge of 125 µC.

**Result:** The equivalent capacitance of the network is 5 µF, and each capacitor (C₁ through C₅) carries a charge of 125 µC, exactly matching the given correct option.