Five artwork labels — A, B, C, D, and E — are arranged in a horizontal display from left to right.

C is placed fourth, with D immediately before it. A occupies the last position. E is somewhere to the right of B.

Which label is in the first position?

The correct answer is B.

Step-by-step explanation:

We have five artwork labels — A, B, C, D, and E — arranged in a horizontal display from left to right across five positions numbered 1 to 5:

$\text{Position 1},\text{Position 2},\text{Position 3},\text{Position 4},\text{Position 5}$

We can deduce the exact order of the labels by analyzing the given conditions step-by-step:

Step 1: Determine the positions of A, C, and D
- "A occupies the last position": Since there are 5 positions in total, Position 5 must be A.
- "C is placed fourth": Position 4 must be C.
- "D immediately before C": Since C is in Position 4, the label immediately before it (Position 3) must be D.

Now, positions 3, 4, and 5 are fixed:

$\text{\_},\text{\_},\text{D},\text{C},\text{A}$

Step 2: Determine the positions of B and E
- The remaining open positions are Position 1 and Position 2.
- The remaining labels to place are B and E.
- "E is somewhere to the right of B": This means B must come before E in the sequence. Therefore, B must occupy Position 1 and E must occupy Position 2.

Final Sequence from Left to Right:

$\text{Position 1: B}\Rightarrow \text{Position 2: E}\Rightarrow \text{Position 3: D}\Rightarrow \text{Position 4: C}\Rightarrow \text{Position 5: A}$

Therefore, label B is in the first position.