Question Details

For a first-order reaction R → P at a given temperature, k is the rate constant. For this reaction, at the given temperature, the concentrations of R and P at a time t are [R] and [P], respectively. The correct graphical representation(s) for this reaction is(are)

Options

A

[P] vs t (increasing curve)

B

d[R]/dt vs [R] (increasing straight line)

C

d[P]/dt vs t (decreasing curve)

D

k vs t (horizontal line)

Show Answer

Correct Answer :

Option C

d[P]/dt vs t (decreasing curve)

Option D

k vs t (horizontal line)

Solution :

The correct graphical representations for the given first-order reaction are d[P]/dt vs t (decreasing curve) and k vs t (horizontal line).

Step-by-step Analysis and Derivations:

For a first-order reaction RP with rate constant k:

1. Analysis of Rate Constant vs Time (k vs t):
The rate constant k of a chemical reaction depends only on temperature and catalyst. It is independent of time t or the initial concentration of reactants.
Therefore, a plot of k versus t is a horizontal straight line parallel to the time axis.
This corresponds to graph (D) shown in the image.

2. Analysis of Rate of Formation vs Time (d[P]/dt vs t):
For a first-order reaction, the rate of disappearance of reactant R or the rate of formation of product P is directly proportional to the concentration of reactant R at that instant:

d[P]dt=-d[R]dt=k[R]


The concentration of reactant R at any time t for a first-order reaction is given by the integrated rate law:

[R]=[R]0e-kt


Substituting [R] into the rate expression gives:

d[P]dt=k[R]0e-kt


This equation represents an exponentially decreasing curve with respect to time t.
This corresponds to graph (C) shown in the image.

3. Analysis of Other Graphs for Comparison:
- [P] vs t: The concentration of product P is given by [P]=[R]0(1-e-kt). This is an exponentially increasing curve that approaches [R]0 asymptotically with a decreasing slope (concave downward), whereas graph (A) shows an upward exponential growth curve, which is incorrect.
- d[R]/dt vs [R]: Graph (B) shows a straight line starting from the origin, but rate of consumption is technically -d[R]/dt=k[R].

Thus, graphs (C) and (D) correctly represent the behavior of the given first-order reaction.

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  • JEE
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  • JEE
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