For which discovery did Henri Becquerel receive the Nobel Prize in Physics in 1903?

The correct option is Spontaneous Radioactivity.

Step-by-Step Explanation:

1. Discovery of Radioactivity:
In 1896, French physicist Henri Becquerel discovered that uranium salts spontaneously emitted radiation that could penetrate black paper and expose a photographic plate, without requiring exposure to sunlight. This phenomenon was identified as spontaneous radioactivity.

2. Nobel Prize Recognition:
In 1903, Henri Becquerel was awarded one half of the Nobel Prize in Physics for his discovery of spontaneous radioactivity. The other half of the prize was jointly awarded to Marie Curie and Pierre Curie for their research on the radiation phenomena discovered by Becquerel.

Therefore, Henri Becquerel received the Nobel Prize in Physics in 1903 for the discovery of Spontaneous Radioactivity.