Question Details

Four teams - Red (R), Blue (B), Green (G), and Yellow (Y) are competing in the final four rounds of the Inter-School Science Olympiad, labeled Round A, Round B, Round C, and Round D. Each round consists of one match between two teams, and every team plays exactly two matches. No team plays the same opponent more than once. The final schedule must adhere to the following rules:


Rule 1 (Consecutive Play): The Green team (G) must play their two matches in consecutive rounds.
Rule 2 (Fixed Appearance): The Yellow team (Y) must play in Round B.
Rule 3 (Positional Constraint): The Red team (R) must play against the Blue team (B) in a round that is immediately before a round in which neither R nor B is playing.
Rule 4 (Timing): The Blue team’s (B) first match must occur in an earlier round than the Green team’s (G) first match.
Rule 5 (Opponent Link): The team that plays against the Red team (R) in the round that is not against the Blue team (B), is the same team that plays in Round D.


Applying the Positional Constraint Based on all the rules, particularly Rule 3, which of the following matches must be scheduled for Round A?

Options

A

Red vs. Green

B

Red vs. Yellow

C

Red vs. Blue

D

Blue vs. Yellow

Show Answer

Correct Answer :

Option C

Red vs. Blue

Solution :

The correct answer is Red vs. Blue.

Let's analyze the given rules step-by-step to deduce the complete schedule for the four rounds (Round A, Round B, Round C, and Round D).
Each round features 1 match between 2 teams. Across the 4 rounds, there are a total of 4 matches.
Since there are 4 teams and each team plays exactly 2 matches, every team appears twice in the schedule.

Step 1: Analyze Rule 3 (Positional Constraint)
Rule 3 states: "The Red team (R) must play against the Blue team (B) in a round that is immediately before a round in which neither R nor B is playing."
Let the round where Red plays Blue (R vs. B) be Round X.
The round immediately following Round X (i.e., Round X + 1) cannot feature team R or team B.
Therefore, Round X + 1 must be a match between the other two teams: Green and Yellow (G vs. Y).
Since Round X + 1 exists, Round X cannot be Round D. Thus, the match R vs. B must occur in Round A, Round B, or Round C.

Step 2: Determine the Position of the G vs. Y Match
According to Rule 2, Yellow (Y) must play in Round B.
If the match G vs. Y were scheduled for Round B, then Round X would have to be Round A (since G vs. Y is in Round X + 1).
Let's check if G vs. Y can be in Round B:
If Round A = R vs. B, and Round B = G vs. Y:
• Blue's (B) first match is in Round A.
• Green's (G) first match is in Round B.
This satisfies Rule 4 ("The Blue team’s first match must occur in an earlier round than the Green team’s first match").
Now let's check Green's (G) matches:
By Rule 1, Green (G) plays in consecutive rounds. Since G plays in Round B, G's second match must be in Round C.
The remaining teams to play G in Round C cannot be Y (no repeat opponents) or G itself. So G must play either R or B in Round C.
By Rule 5, the team that plays against R in R's non-B match is the team that plays in Round D.
In Round D, the match cannot involve G (since G plays in B and C), so Round D must be between R and Y or B and Y.
Everything is perfectly consistent when Round A is R vs. B.

Step 3: Verify why R vs. B must be in Round A
If R vs. B were in Round B (so X = Round B):
Then G vs. Y must be in Round C.
Rule 2 requires Y to play in Round B, but Round B is already R vs. B. Thus, Y cannot play in Round B, which violates Rule 2. Therefore, R vs. B cannot be in Round B.
If R vs. B were in Round C (so X = Round C):
Then G vs. Y must be in Round D.
Since G's first match would be in Round D (or Round C/D), G plays in Round D. But Rule 4 states Blue's first match must be earlier than Green's first match. If Blue plays in Round C, Green's first match would have to be before Round C (i.e. Round A or B). If G's first match is in Round A or B, but G vs. Y is in Round D, then by Rule 1 (consecutive play), G must play in C and D or A and B. But G vs. Y is in Round D, so G plays in C and D. If G plays in C, then Round C has 3 teams (R, B, G), which is impossible since each round is 1 match between 2 teams.

Thus, the match scheduled for Round A must be Red vs. Blue.

Unlock Our Free Library

Access expert-curated educational resources and study materials—completely free.

Discover more resources

You may also like

Mock Tests

View All
  • CLAT
  • intermediate
  • 2 hours
  • current affairs, general knowledge, legal reasoning, logical reasoning, quant

  • CLAT
  • intermediate
  • 2 hours
  • current affairs, english, general knowledge, legal reasoning, logical reasoning, quant

Ask AI Tutor
5 left
Q1 View Question & Options
AI Tutor is solving this question...
Reading question context & options...