Question Details

Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason.

Assertion (A) :- The potential (V) at any axial point, at 2 m distance (r) from the centre of the dipole of dipole moment vector P̅ of magnitude, 4 × 10-6 C m, is ±9 × 103 V.

(Take 1/4π∈0 = 9 × 109SI Units)

Reason (R) :- V = ± (2P/4π∈0r2), where r is the distance of any axial point, situated at 2 m from the centre of the dipole. In the light of the above statements, choose the correct answer from the options given below :


Options

A

Both A and R are true and R is the correct explanation of A.

B

Both A and R are true and R is NOT the correct explanation of A.

C

A is true but R is false.

D

A is false but R is true.

Show Answer

Correct Answer :

Option C

A is true but R is false.

A is true but R is false.

Solution :

The given data are:

  • Dipole moment magnitude P = 4 × 10-6 C·m
  • Distance from the centre to the axial point r = 2 m
  • 1 / (4π ε₀) = 9 × 109 SI

For a point on the axial line of an electric dipole, the electric potential is

V = \frac{1}{4\pi\varepsilon_0}\,\frac{P}{r^{2}}

Substituting the numbers:

V = 9\times10^{9}\times\frac{4\times10^{-6}}{(2)^{2}}

Since (2)² = 4, the expression simplifies to

V = 9\times10^{9}\times\frac{4\times10^{-6}}{4}

Cancel the factor 4:

V = 9\times10^{9}\times10^{-6}

Multiplying the powers of ten gives

V = 9\times10^{3}\ \text{V}

Because the potential on the axial line can be positive in one direction and negative in the opposite direction, the magnitude is ± 9 × 10³ V, exactly as stated in the Assertion.

Now examine the Reason. It claims

V = \pm\frac{2P}{4\pi\varepsilon_0\,r^{2}}

If we evaluate this expression, the extra factor 2 would double the result, giving ± 1.8 × 10⁴ V, which does not match the given value.

Thus the Reason uses an incorrect formula for the axial potential of a dipole.

Consequently:

  • Assertion (A) is true.
  • Reason (R) is false.

Therefore the correct option is “A is true but R is false.”

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