How many letters are between the 1st from left and 2nd from right in the word COMPETITION, when arranged alphabetically?

The correct option is 8.

Let's solve the problem step-by-step to find the number of letters between the specified positions.

Step 1: Write down the original word.
The given word is COMPETITION.

Step 2: List all the letters and arrange them alphabetically.
Let's break down the letters of the word COMPETITION:
C, O, M, P, E, T, I, T, I, O, N

Sorting these 11 letters in alphabetical order (A to Z) gives:
1. C
2. E
3. I
4. I
5. M
6. N
7. O
8. O
9. P
10. T
11. T

So, the alphabetically arranged sequence is: C, E, I, I, M, N, O, O, P, T, T.

Step 3: Identify the required positions.
• The 1st letter from the left is the 1st element: C.
• The 2nd letter from the right is the 10th element (or 2nd from the end): T.

Step 4: Count the letters between these two positions.
The letters lying strictly between the 1st position (C) and the 10th position (T) are from position 2 to position 9:
Position 2: E
Position 3: I
Position 4: I
Position 5: M
Position 6: N
Position 7: O
Position 8: O
Position 9: P

Counting these positions:
$9-2+1=8$

Therefore, there are 8 letters between the 1st letter from the left and the 2nd letter from the right when the word COMPETITION is arranged alphabetically.