How many pairs of letters are there in the word 'DOMINANT' which have as many letters between them in the word as in the English alphabetical series (in both forward and backward directions)?

The correct answer is One.

To find the number of pairs of letters in the word DOMINANT that have as many letters between them in the word as in the English alphabetical series, we analyze the word in both forward (left to right) and backward (right to left) directions.

Let us first list the positions of the letters in the word alongside their corresponding numerical positions in the English alphabet:
1. D - 4
2. O - 15
3. M - 13
4. I - 9
5. N - 14
6. A - 1
7. N - 14
8. T - 20

Checking in the Forward Direction (Left to Right):
- D (4): D, E, F, G, H, I, J, K (No matching pair)
- O (15): O, P, Q, R, S, T (No matching pair)
- M (13): M, N, O, P, Q, R (No matching pair)
- I (9): I, J, K, L, M (No matching pair)
- N (14): N, O, P, Q (No matching pair)
- A (1): A, B, C (No matching pair)
- N (14): N, O (No matching pair)

Checking in the Backward Direction (Right to Left):
- T (20): T, U, V, W, X, Y, Z (No matching pair)
- N (14 at pos 7): N, O, P, Q, R, S (No matching pair)
- A (1): A, B, C, D, E (No matching pair)
- N (14 at pos 5): N, O, P, Q (No matching pair)
- I (9): I, J, K, L (No matching pair)
- M (13): Counting backwards to O (15), the pair (M, O) has 1 letter between them in the alphabet (N) and 1 letter between them in the word (I).
- O (15): O, P (No matching pair)

Therefore, there is 1 pair of letters that satisfies the given condition.