In the numeral ‘94827651’, how many digits will retain their original positions after all the digits are arranged in ascending order from right to left?

The correct option is Two.

Given numeral: 94827651

Let us note the original position of each digit from left to right (positions 1 to 8):
1^st position: 9
2^nd position: 4
3^rd position: 8
4^th position: 2
5^th position: 7
6^th position: 6
7^th position: 5
8^th position: 1

The digits contained in the numeral, when written in ascending order (smallest to largest), are:
1, 2, 4, 5, 6, 7, 8, 9

We are asked to arrange these digits in ascending order from right to left. This means placing the smallest digit at the rightmost position (8^th position) and filling towards the left with increasing digits:
8^th position (rightmost): 1
7^th position: 2
6^th position: 4
5^th position: 5
4^th position: 6
3^rd position: 7
2^nd position: 8
1^st position (leftmost): 9

Comparing the original digits at each position with the new digits:
• 1^st position: Original = 9, New = 9 (Retained)
• 2^nd position: Original = 4, New = 8
• 3^rd position: Original = 8, New = 7
• 4^th position: Original = 2, New = 6
• 5^th position: Original = 7, New = 5
• 6^th position: Original = 6, New = 4
• 7^th position: Original = 5, New = 2
• 8^th position: Original = 1, New = 1 (Retained)

Only two digits, 9 (at position 1) and 1 (at position 8), retain their original positions.
Therefore, the number of digits that retain their original positions is Two.