Identify the major product C formed in the following reaction sequence:

The correct option is propylamine.

Let us analyze the reaction sequence step-by-step:

Step 1: Formation of compound A
The starting material is 1-iodopropane (${\mathrm{CH}}_3-{\mathrm{CH}}_2-{\mathrm{CH}}_2-I$). When treated with sodium cyanide ($\mathrm{NaCN}$), a nucleophilic substitution ($S_{N}2$) reaction occurs, where the cyanide ion (${\mathrm{CN}}^{-}$) replaces the iodide ion ($I^{-}$). This increases the carbon chain length by one carbon atom.
${\mathrm{CH}}_3{\mathrm{CH}}_2{\mathrm{CH}}_{2}I+\mathrm{NaCN}\to {\mathrm{CH}}_3{\mathrm{CH}}_2{\mathrm{CH}}_2\mathrm{CN}+\mathrm{NaI}$
Thus, compound A is butanenitrile (${\mathrm{CH}}_3-{\mathrm{CH}}_2-{\mathrm{CH}}_2-\mathrm{CN}$).

Step 2: Formation of compound B
Partial hydrolysis of the nitrile compound A in the presence of hydroxide ions (${\mathrm{OH}}^{-}$) yields an amide. Under mild basic conditions, the nitrile group ($-C\equiv N$) is partially hydrolyzed to a primary amide group ($-{\mathrm{CONH}}_2$):
${\mathrm{CH}}_3{\mathrm{CH}}_2{\mathrm{CH}}_2\mathrm{CN}\underset{\text{Partial hydrolysis}}{\overset{{\mathrm{OH}}^{-}}{\to }}{\mathrm{CH}}_3{\mathrm{CH}}_2{\mathrm{CH}}_2{\mathrm{CONH}}_2$
Thus, compound B is butanamide (${\mathrm{CH}}_3-{\mathrm{CH}}_2-{\mathrm{CH}}_2-{\mathrm{CONH}}_2$).

Step 3: Formation of major product C
When the primary amide butanamide (compound B) reacts with bromine (${\mathrm{Br}}_2$) in the presence of sodium hydroxide ($\mathrm{NaOH}$), it undergoes the Hoffmann bromamide degradation reaction. This reaction degrades the amide to a primary amine containing one carbon atom less than the starting amide by eliminating the carbonyl carbon as a carbonate ion (${\mathrm{CO}}_3^{2-}$):
${\mathrm{CH}}_3{\mathrm{CH}}_2{\mathrm{CH}}_2{\mathrm{CONH}}_2+{\mathrm{Br}}_2+4\mathrm{NaOH}\to {\mathrm{CH}}_3{\mathrm{CH}}_2{\mathrm{CH}}_2{\mathrm{NH}}_2+{\mathrm{Na}}_2{\mathrm{CO}}_3+2\mathrm{NaBr}+2H_{2}O$
Thus, the major product C is propylamine (${\mathrm{CH}}_3-{\mathrm{CH}}_2-{\mathrm{CH}}_2-{\mathrm{NH}}_2$).