If 1 is added to each even digit and 2 is subtracted from each odd digit in the number 39225685459, then how many digits will appear more than twice in the new number thus formed?

The correct option is Two.

Let's follow the given instructions step-by-step to form the new number and analyze the frequency of each digit.

Step 1: Write down the original number
The original number given is 39225685459.

Step 2: Apply the transformation rules to each digit
Rule 1: If the digit is even, add 1 to it.
Rule 2: If the digit is odd, subtract 2 from it.

Let's process each digit in sequence from left to right:

1. First digit: 3 (odd) ⇒ 3 - 2 = 1
2. Second digit: 9 (odd) ⇒ 9 - 2 = 7
3. Third digit: 2 (even) ⇒ 2 + 1 = 3
4. Fourth digit: 2 (even) ⇒ 2 + 1 = 3
5. Fifth digit: 5 (odd) ⇒ 5 - 2 = 3
6. Sixth digit: 6 (even) ⇒ 6 + 1 = 7
7. Seventh digit: 8 (even) ⇒ 8 + 1 = 9
8. Eighth digit: 5 (odd) ⇒ 5 - 2 = 3
9. Ninth digit: 4 (even) ⇒ 4 + 1 = 5
10. Tenth digit: 5 (odd) ⇒ 5 - 2 = 3
11. Eleventh digit: 9 (odd) ⇒ 9 - 2 = 7

Step 3: Write down the new number formed
The new number thus formed is 17333793537.

Step 4: Count the frequency of each digit in the new number
Let's list the occurrence count for every digit present in 17333793537:

• Digit 1 appears 1 time.
• Digit 3 appears 5 times (at 3rd, 4th, 5th, 8th, and 10th positions).
• Digit 5 appears 1 time.
• Digit 7 appears 3 times (at 2nd, 6th, and 11th positions).
• Digit 9 appears 1 time.

Step 5: Identify digits that appear more than twice
"More than twice" means appearing 3 or more times (frequency > 2).

• Digit 3 appears 5 times, which is more than twice.
• Digit 7 appears 3 times, which is more than twice.

Therefore, there are exactly 2 digits (namely 3 and 7) that appear more than twice in the new number.