If 3 April 1996 was Wednesday, then what was the day of the week on 7 April 2001?

The correct option is Saturday.

To find the day of the week on 7 April 2001, given that 3 April 1996 was a Wednesday, we can calculate the total number of odd days between the two dates.

Step 1: Calculate odd days from 3 April 1996 to 3 April 2001

The period covers 5 years: 1997, 1998, 1999, 2000, and 2001.

Note: The leap year in this period is 2000 (which adds 2 odd days). Although 1996 is a leap year, February 1996 has already passed before 3 April 1996, so it does not add an extra leap day to this period.

Number of ordinary years = 4 (1997, 1998, 1999, 2001)

Number of leap years = 1 (2000)

Odd days from 4 ordinary years = $4\times 1=4$ odd days

Odd days from 1 leap year = $1\times 2=2$ odd days

Total odd days from 3 April 1996 to 3 April 2001 = $4+2=6$ odd days.

Step 2: Calculate odd days from 3 April 2001 to 7 April 2001

The number of days from 3 April 2001 to 7 April 2001 is $7-3=4$ days.

Step 3: Total odd days

Total odd days = $6+4=10$ days.

Dividing by 7 to find the remainder: $10÷7=1$ week and $3$ odd days.

Step 4: Determine the final day

Adding 3 days to Wednesday:

Wednesday + 3 days = Saturday.

Therefore, 7 April 2001 was a Saturday.