If 56 ÷ 4 + p × 3 – 24 ÷ 12 + 4 = 21 ÷ 3 + 3, then the value of p is:

The correct answer is -2.

To find the value of $p$, we need to solve the given equation step-by-step using the BODMAS (or PEMDAS) rule, which dictates the order of operations: Division and Multiplication first (from left to right), followed by Addition and Subtraction.

The given equation is:

$56÷4+p\times 3-24÷12+4=21÷3+3$

Step 1: Perform the division operations on both sides of the equation.
On the left-hand side (LHS):
$56÷4=14$
$24÷12=2$
On the right-hand side (RHS):
$21÷3=7$

Substitute these values back into the equation:

$14+p\times 3-2+4=7+3$

Step 2: Simplify the multiplication and addition/subtraction.
Simplify the term $p\times 3$ to $3p$.
Now simplify the constants on both sides of the equation:

LHS:
$14-2+4+3p=16+3p$

RHS:
$7+3=10$

Step 3: Equate LHS and RHS and solve for $p$.

$16+3p=10$

Subtract 16 from both sides of the equation:

$3p=10-16$

$3p=-6$

Divide both sides by 3:

$p=\frac{-6}{3}$

$p=-2$

Therefore, the value of $p$ is -2.