If all the odd digits are removed from the series, which digit will be 9th from the left end?
Observe the given digit series carefully and answer the questions based on it.
6 8 4 9 3 4 8 9 5 9 2 7 6 1 8 4 3 9 2 5

The correct option is 4.

Let's solve the problem step-by-step by analyzing the given series of digits.

Step 1: Write down the original digit series
The given digit series is:
6, 8, 4, 9, 3, 4, 8, 9, 5, 9, 2, 7, 6, 1, 8, 4, 3, 9, 2, 5

Step 2: Identify and remove all odd digits
The odd digits present in this series are 9, 3, 5, 7, and 1.
Removing all the odd digits from the original series leaves only the even digits (6, 8, 4, 2):

Original with odd digits highlighted to be removed:
6, 8, 4, 9, 3, 4, 8, 9, 5, 9, 2, 7, 6, 1, 8, 4, 3, 9, 2, 5

Step 3: Write down the new series after removing all odd digits
The remaining series of even digits from left to right is:
6, 8, 4, 4, 8, 2, 6, 8, 4, 2

Step 4: Count to find the 9th digit from the left end
Let's list the positions from the left end:
1st digit: 6
2nd digit: 8
3rd digit: 4
4th digit: 4
5th digit: 8
6th digit: 2
7th digit: 6
8th digit: 8
9th digit: 4
10th digit: 2

Therefore, the 9th digit from the left end after removing all odd digits is 4.