If E and G respectively denote energy and gravitational constant, then E/G has the dimensions of :

We are asked to find the dimensional formula of the ratio E ⁄ G, where E is energy and G is the gravitational constant.

First, write down the dimensions of energy.

$E=M{L}^2{T}^{-2}$

Next, obtain the dimensions of G from Newton’s law of universal gravitation:

$F=GM$₁M₂r‑2

Re‑arranging gives G = F r² ⁄ (M₁ M₂). The dimensions of force are mass × length × time⁻²:

$F=ML{T}^{-2}$

Therefore:

$G=\frac{F{L}^2}{M^2}=M^{-1}{L}^3{T}^{-2}$

Now form the ratio E ⁄ G:

$\frac{E}{G}=\frac{M^1}{L^2}÷\frac{M^{-1}}{L^3}$

Dividing by a fraction is the same as multiplying by its reciprocal:

$\frac{E}{G}=M^1{L}^2{T}^{-2}·M^1{L}^{-3}{T}^2$

Combine the exponents for each fundamental dimension:

$M^2{L}^{-1}{T}^0$

Thus the dimensional formula of E ⁄ G is [M²] [L⁻¹] [T⁰], which matches the given correct option.