If ‘I’ stands for ‘×’, ‘J’ stands for ‘+’, ‘K’ stands for ‘÷’ and ‘L’ stands for ‘−’, what will come in place of the question mark (?) in the following equation?
17 I (11 L 8 J 4) L 148 K 4 J 22 = ?

The correct answer is 104.

To solve the equation, we must first replace each letter with its corresponding mathematical operator as defined below:
‘I’ stands for ‘×’ (Multiplication)
‘J’ stands for ‘+’ (Addition)
‘K’ stands for ‘÷’ (Division)
‘L’ stands for ‘−’ (Subtraction)

Let's write down the original equation:
$17 \text{I} (11 \text{L} 8 \text{J} 4) \text{L} 148 \text{K} 4 \text{J} 22=?$

After substituting the operator codes, we get:
$17\times (11-8+4)-148÷4+22$

Now, we evaluate this expression step-by-step using the standard BODMAS (Brackets, Orders, Division, Multiplication, Addition, Subtraction) rule:

Step 1: Solve the expression inside the brackets first
$(11-8+4)=3+4=7$

Substituting this back into the equation yields:
$17\times 7-148÷4+22$

Step 2: Perform the division operation
$148÷4=37$

Updating our equation, we get:
$17\times 7-37+22$

Step 3: Perform the multiplication operation
$17\times 7=119$

Now the equation simplifies to:
$119-37+22$

Step 4: Perform addition and subtraction from left to right
$119-37+22=82+22=104$

Thus, the value that replaces the question mark in the equation is 104.